CVE-2026-50210
Executive Summary
CVE-2026-50210 exposes a critical cryptographic weakness in an embedded device (vendor: Device). The implementation uses AES-CBC encryption with static, zero-filled Initialization Vectors (IVs). This flaw allows an attacker who can observe multiple encrypted packets to perform replay attacks and, under known-plaintext conditions, decrypt sensitive data. The vulnerability is unpatched, and no public proof-of-concept code is available at this time.
Impact: An attacker within network proximity (AV:A) can replay captured encrypted commands or data, potentially gaining unauthorized control or access. If the attacker knows any plaintext-ciphertext pair, they can decrypt other blocks due to the static IV.
Affected Ecosystem: This is a hardware/firmware vulnerability in a specific device. No supply chain package (NPM, PyPI, Go, Ruby) is involved.
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CVSS Breakdown & Threat Level
- Attack Vector (AV): Adjacent Network (AV:A) – attacker must be on the same network segment.
- Attack Complexity (AC): Low (AC:L) – no special conditions required.
- Privileges Required (PR): None (PR:N) – no authentication needed to capture traffic.
- User Interaction (UI): None (UI:N) – no user action required.
- Scope (S): Unchanged (S:U) – exploitation does not cross trust boundaries.
- Confidentiality (C): High (C:H) – full decryption of encrypted data possible.
- Integrity (I): High (I:H) – replay attacks can inject malicious commands.
- Availability (A): High (A:H) – replay could cause denial of service or device malfunction.
CVSS Score: 8.8 (High)
Threat Level: High. The static IV makes the encryption deterministic, enabling block-by-block decryption with known plaintext and trivial replay attacks.
Deep Dive & Mechanics
AES-CBC (Cipher Block Chaining) requires a unique, unpredictable IV for each encryption operation to ensure that identical plaintext blocks produce different ciphertext blocks. When the IV is static (e.g., all zeros), the encryption becomes deterministic:
- Replay Attack: An attacker can capture a valid encrypted packet (e.g., "unlock door") and replay it later to achieve the same effect.
- Known-Plaintext Decryption: If the attacker knows the plaintext for one block (e.g., a fixed header), they can XOR it with the ciphertext to recover the IV (which is zero) and then decrypt subsequent blocks using the CBC chain.
Technical Flow:
- Device encrypts plaintext
Pusing AES-CBC with IV = 0x00000000000000000000000000000000. - Ciphertext
C1 = AES_encrypt(P1 XOR IV). - Since IV is zero,
C1 = AES_encrypt(P1). - For subsequent blocks:
Ci = AES_encrypt(Pi XOR Ci-1). - An attacker capturing
C1, C2, ...can replay the entire ciphertext. - If attacker knows
P1, they can computeAES_decrypt(C1) = P1and then useC1to decryptP2viaP2 = AES_decrypt(C2) XOR C1.
Vulnerable vs. Patched Code
Vulnerable Implementation (Conceptual C):
#include <openssl/evp.h>
#include <string.h>
void encrypt_data(const unsigned char *plaintext, int plaintext_len,
unsigned char *ciphertext) {
EVP_CIPHER_CTX *ctx = EVP_CIPHER_CTX_new();
unsigned char key[16] = {0x2b, 0x7e, 0x15, 0x16, 0x28, 0xae, 0xd2, 0xa6,
0xab, 0xf7, 0x15, 0x88, 0x09, 0xcf, 0x4f, 0x3c};
unsigned char iv[16] = {0}; // STATIC ZERO IV - VULNERABLE
EVP_EncryptInit_ex(ctx, EVP_aes_128_cbc(), NULL, key, iv);
int len;
EVP_EncryptUpdate(ctx, ciphertext, &len, plaintext, plaintext_len);
int ciphertext_len = len;
EVP_EncryptFinal_ex(ctx, ciphertext + len, &len);
ciphertext_len += len;
EVP_CIPHER_CTX_free(ctx);
}
Patched Implementation (Conceptual C):
#include <openssl/evp.h>
#include <openssl/rand.h>
#include <string.h>
void encrypt_data(const unsigned char *plaintext, int plaintext_len,
unsigned char *ciphertext, unsigned char *iv_out) {
EVP_CIPHER_CTX *ctx = EVP_CIPHER_CTX_new();
unsigned char key[16] = {0x2b, 0x7e, 0x15, 0x16, 0x28, 0xae, 0xd2, 0xa6,
0xab, 0xf7, 0x15, 0x88, 0x09, 0xcf, 0x4f, 0x3c};
unsigned char iv[16];
// Generate random IV
if (!RAND_bytes(iv, sizeof(iv))) {
// handle error
}
EVP_EncryptInit_ex(ctx, EVP_aes_128_cbc(), NULL, key, iv);
int len;
EVP_EncryptUpdate(ctx, ciphertext, &len, plaintext, plaintext_len);
int ciphertext_len = len;
EVP_EncryptFinal_ex(ctx, ciphertext + len, &len);
ciphertext_len += len;
EVP_CIPHER_CTX_free(ctx);
// Prepend IV to ciphertext for transmission
memcpy(iv_out, iv, 16);
memmove(ciphertext + 16, ciphertext, ciphertext_len);
memcpy(ciphertext, iv, 16);
}
Key Difference: The patched version generates a cryptographically random IV using RAND_bytes() and prepends it to the ciphertext. The receiver must extract the IV from the first 16 bytes before decryption.
Exploitation & Lab Setup
Red Team (Attacker)
Lab Environment:
- Target device with CVE-2026-50210 (e.g., a smart lock or IoT sensor).
- Attacker machine with Python and Scapy or Wireshark.
- Network access to the device (e.g., same Wi-Fi).
Exploitation Steps:
Capture Encrypted Traffic:
sudo tcpdump -i wlan0 -w capture.pcapTrigger a known action (e.g., press unlock button) to capture a known-plaintext pair.
Extract Ciphertext: Use Wireshark or Scapy to extract the encrypted payload.
Replay Attack:
from scapy.all import * packets = rdpcap('capture.pcap') # Assume packet with encrypted command is at index 5 replay_pkt = packets[5] sendp(replay_pkt, iface='wlan0')Known-Plaintext Decryption (if plaintext known):
from Crypto.Cipher import AES import binascii key = binascii.unhexlify('2b7e151628aed2a6abf7158809cf4f3c') iv = b'\x00' * 16 ciphertext = binascii.unhexlify('...') # from capture cipher = AES.new(key, AES.MODE_CBC, iv) plaintext = cipher.decrypt(ciphertext) print(plaintext)
Blue Team (Defender)
Detection & Mitigation:
- Monitor for repeated identical encrypted packets (replay indicator).
- Implement network-level anomaly detection for unusual command sequences.
- If possible, apply firmware update once vendor releases patch.
- As a workaround, use a VPN or TLS tunnel to encrypt the entire communication, rendering the static IV irrelevant.
Indicators of Compromise (IOCs)
- Network IOCs:
- Repeated identical encrypted payloads within short time windows.
- Encrypted packets with all-zero IV (first 16 bytes of payload are zeros).
- Host IOCs:
- Unexpected device behavior (e.g., door unlocking without user action).
- Logs showing repeated commands from same source MAC.
Detection Engineering
YARA Rule
rule CVE_2026_50210_Static_IV {
meta:
description = "Detects AES-CBC encrypted data with static zero IV"
author = "Valters IT"
date = "2026-01-01"
cve = "CVE-2026-50210"
strings:
$iv_zero = {00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00}
condition:
$iv_zero at 0
}
Sigma Rule
title: Detection of Replay Attack via Static IV
id: 8a9b7c6d-5e4f-3a2b-1c0d-9e8f7a6b5c4d
status: experimental
description: Detects repeated identical encrypted payloads indicating replay attack
author: Valters IT
logsource:
category: network_connection
product: suricata
detection:
selection:
event_type: alert
alert.signature_id: 202650210
condition: selection
fields:
- src_ip
- dest_ip
- payload
falsepositives:
- Legitimate retransmissions
level: high
Suricata Rule
alert tcp any any -> any any (msg:"CVE-2026-50210 - Potential Replay Attack - Static IV Detected"; content:"|00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00|"; offset:0; depth:16; sid:202650210; rev:1;)
Remediation & Mitigation
Immediate Actions:
- Network Segmentation: Isolate the vulnerable device on a separate VLAN to limit attack surface.
- Traffic Encryption: Use a VPN or TLS tunnel to encapsulate device traffic, negating the static IV weakness.
- Monitor for Replays: Deploy the Suricata rule above to detect repeated payloads.
Long-Term Fix:
- Vendor must release a firmware update that generates random IVs for each encryption session.
- If device supports firmware updates, apply immediately.
- If not, replace the device with a cryptographically secure alternative.
Valters IT Signature: This report was generated by Valters IT DevSecOps AI. For questions, contact security@valters-it.com.